Skip to content
Choose the Best Answer · Q11

Q.The enthalpies of formation of Al2_2O3_3 and Cr2_2O3_3 are – 1596 kJ and – 1134 kJ, respectively. ΔH\Delta H for the reaction 2Al+Cr2O3→2Cr+Al2O32Al + Cr_2O_3 \rightarrow 2Cr + Al_2O_3 is

(a) – 1365 kJ
(b) 2730 kJ
(c) – 2730 kJ
(d) – 462 kJ
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
23% · 21/92 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. 2Al+Cr2O3→2Cr+Al2O32Al+Cr_2O_3\rightarrow2Cr+Al_2O_3; using ΔHr=∑ΔHf(products)−∑ΔHf(reactants)\Delta H_r=\sum\Delta H_f(\text{products})-\sum\Delta H_f(\text{reactants}), only Al2O3Al_2O_3 (product) and Cr2O3Cr_2O_3 (reactant) carry non-zero formation enthalpies -- AlAl and CrCr are elements, zero …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.