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Write Brief Answer · Q46

Q.A gas mixture of 3.67 lit of ethylene and methane on complete combustion at 25∘25^\circC and at 1 atm pressure produce 6.11 lit of carbondioxide. Find out the amount of heat evolved in kJ, during this combustion. (ΔHC(CH4)=−890\Delta H_C(CH_4) = -890 kJ mol−1^{-1} and ΔHC(C2H4)=−1423\Delta H_C(C_2H_4) = -1423 kJ mol−1^{-1})

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Step 1. Let xx = volume CH4_4, yy = volume C2_2H4_4; x+y=3.67x+y=3.67 L. CH4→_4\rightarrow1 CO2_2 each, C2_2H4→_4\rightarrow2 CO2_2 each, so (by volume, same T,PT,P): x+2y=6.11x+2y=6.11.

Step 2. Substituting x=3.67−yx=3.67-y: (3.67−y)+2y=6.11⇒3.67+y=6.11⇒y=2.44(3.67-y)+2y=6.11 \Rightarrow 3.67+y=6.11 \Rightarrow y=2.44 L; so x=3.67−2.44=1.23x=3.67-2.44=1.23 L. …

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