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Exercise 2.13 · Q8

Q.If log⁡x0.25=4\log_{\sqrt x}0.25=4, then the value of xx is

(1) 0.50.5
(2) 2.52.5
(3) 1.51.5
(4) 1.251.25
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Step 1. log⁡x0.25=4⇒(x)4=0.25\log_{\sqrt x}0.25=4\Rightarrow(\sqrt x)^4=0.25.

Step 2. (x)4=x2=0.25⇒x2=0.25⇒x=0.5(\sqrt x)^4=x^2=0.25\Rightarrow x^2=0.25\Rightarrow x=0.5 (taking the positive root, since xx must be pos …

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