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Exercise 2.3 · Q4

Q.Solve:

(i) 3(x−2)5≤5(2−x)3\dfrac{3(x-2)}{5}\le\dfrac{5(2-x)}{3}.
(ii) 5−x3<x2−4\dfrac{5-x}{3}<\dfrac{x}{2}-4.
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Step 1 (i). Multiply both sides by 1515 (positive, no flip): 9(x−2)≤25(2−x)9(x-2)\le25(2-x).

Step 2 (i). Expand: 9x−18≤50−25x⇒34x≤68⇒x≤29x-18\le50-25x\Rightarrow34x\le68\Rightarrow x\le2. Solution: (−∞,2](-\infty,2].

Step 3 (ii). Multiply both sides by 66: 2(5−x)<3x−242(5-x)<3x-24. …

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