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Exercise 9.1 · Q10

Q.Use the graph (Fig. 9.16) to find the limit, if it exists. If the limit does not exist, explain why.
[!FORMULA] lim⁡x→1f(x),where f(x)={x2+2,x≠11,x=1\lim_{x\to1}f(x),\qquad \text{where } f(x)=\begin{cases}x^2+2, & x\ne1\\ 1, & x=1\end{cases}

Graph of f(x) = x^2 + 2 for x != 1 (upward parabola, vertex (0,2)) with an OPEN circle at (1, 3) and a separate SOLID dot at (1, 1) — Mathematics question
Figure
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Step 1. Read the definition/graph. Fig. 9.16 shows the parabola y=x2+2y=x^2+2 with an open circle at (1,3)(1,3) — the height the curve approaches — and a filled dot at (1,1)(1,1), the prescribed value f(1)=1f(1)=1.

Step 2. Use the branch governing values near x=1x=1. For x≠1x\ne1, f(x)=x2+2f(x)=x^2+2.

Step 3. Take the limit. lim⁡x→1(x2+2)=12+2=3\displaystyle\lim_{x\to1}(x^2+2)=1^2+2=3. …

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