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Exercise 9.1 · Q22

Q.Evaluate lim⁡x→3x2−9x−3\displaystyle\lim_{x\to3}\dfrac{x^2-9}{x-3}, if it exists, by finding f(3−)f(3^-) and f(3+)f(3^+).

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Step 1. Try direct substitution. At x=3x=3: 9−90=00\dfrac{9-9}{0}=\dfrac00, indeterminate.

Step 2. Factor and simplify. x2−9=(x−3)(x+3)x^2-9=(x-3)(x+3), so for x≠3x\ne3,

x2−9x−3=(x−3)(x+3)x−3=x+3.\dfrac{x^2-9}{x-3}=\dfrac{(x-3)(x+3)}{x-3}=x+3.

Step 3. Find f(3−)f(3^-). As x→3−x\to3^-, x+3→6x+3\to6.

Step 4. Find f(3+)f(3^+). As x→3+x\to3^+, x+3→6x+3\to6. …

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