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Exercise 9.1 · Q11

Q.Use the graph (Fig. 9.17) to find the limit, if it exists. If the limit does not exist, explain why.
[!FORMULA] lim⁡x→31x−3\lim_{x\to3}\dfrac1{x-3}

Graph of y = 1/(x-3): a rectangular hyperbola with a VERTICAL ASYMPTOTE (dashed) at x=3 — the branch for x<3 goes to -infinity as x->3-, — Mathematics question
Figure
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Step 1. Read the graph. Fig. 9.17 shows y=1x−3y=\dfrac1{x-3} with a vertical asymptote (dashed line) at x=3x=3: the branch to the left of x=3x=3 plunges downward, and the branch to the right shoots upward.

Step 2. Evaluate the left-hand behaviour. As x→3−x\to3^-, x−3x-3 is a small negative number, so 1x−3→−∞\dfrac1{x-3}\to-\infty.

Step 3. Evaluate the right-hand behaviour. As x→3+x\to3^+, x−3x-3 is a small positive number, so 1x−3→+∞\dfrac1{x-3}\to+\infty. …

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