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Mathematics · Ch 9 — Differential Calculus – Limits and Continuity

Removable and Jump Discontinuities

9.3.3

Removable and Jump Discontinuities

Not all discontinuities are the same "kind" — some can be patched by simply reassigning a single function value, while others cannot be patched at all no matter what value is chosen.

Removable discontinuity. Consider f(x)=sin⁡xxf(x)=\dfrac{\sin x}{x}, undefined at x=0x=0 (failure type (1) of Section 9.3). Even though f(0)f(0) does not exist, lim⁡x→0sin⁡xx=1\lim_{x\to0}\dfrac{\sin x}{x}=1 genuinely exists. If a new function hh is defined to agree with ff everywhere except that it is explicitly assigned the value h(0)=1h(0)=1 — exactly the limiting value — then hh becomes continuous at 00: the "hole" in the graph is simply filled in with the single point the limit was always pointing to. Because the discontinuity can be eliminated this way, by redefining a single point, it is called removable.

Definition 9.10. ff, defined on an interval II, has a removable discontinuity at x0∈Ix_0\in I if there exists a function h:I→Rh:I\to\mathbb R with h(x)=f(x)h(x)=f(x) for all x≠x0x\ne x_0, h(x0)=lim⁡x→x0f(x)h(x_0)=\lim_{x\to x_0} f(x), and hh continuous at x0x_0. (Necessarily, for this to even be possible, lim⁡x→x0f(x)\lim_{x\to x_0}f(x) must exist as an ordinary two-sided limit in the first place — it is exactly the value that gets assigned to patch the hole.)

Jump discontinuity. Revisit the tomato-cost function C(x)C(x) from Example 9.38: at x=100x=100, both one-sided limits exist (1616 from the left, 1414 from the right) but they simply disagree, giving a finite jump of height lim⁡x→100−C(x)−lim⁡x→100+C(x)=16−14=2\lim_{x\to100^-}C(x)-\lim_{x\to100^+}C(x)=16-14=2. Unlike the removable case, no single value assigned at x=100x=100 could fix this — reassigning C(100)C(100) only relocates where the dot sits on the graph; it can never make the two approaching branches meet. This is a fundamentally different, unpatchable kind of discontinuity:

Definition 9.11. ff, defined on interval II, has a jump discontinuity at x0∈Ix_0\in I if ff is defined at x0x_0 and both one-sided limits lim⁡x→x0−f(x)\lim_{x\to x_0^-}f(x) and lim⁡x→x0+f(x)\lim_{x\to x_0^+}f(x) exist, but lim⁡x→x0−f(x)≠lim⁡x→x0+f(x)\lim_{x\to x_0^-}f(x)\ne\lim_{x\to x_0^+}f(x).

Distinguishing the two. The dividing line between "removable" and "jump" is exactly whether the two-sided limit exists at all: a removable discontinuity has a perfectly good (single) two-sided limit that the function value simply fails to match, or fails to have at all; a jump discontinuity has two perfectly good but different one-sided limits, so no single two-sided limit exists to be assigned in the first place. …