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Exercise 9.6 · Q12

Q.If f:R→Rf:\mathbb R\to\mathbb R is defined by f(x)=⌊x−3⌋+∣x−4∣f(x)=\lfloor x-3\rfloor+|x-4| for x∈Rx\in\mathbb R, then lim⁡x→3−f(x)\displaystyle\lim_{x\to3^-}f(x) is equal to

(1) −2-2
(2) −1-1
(3) 00
(4) 11
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Step 1. As x→3−x\to3^-, take xx in [2,3)[2,3) so that x−3∈[−1,0)x-3\in[-1,0); on this range ⌊x−3⌋=−1\lfloor x-3\rfloor=-1 (a constant).

Step 2. Also on this range x<4x<4, so ∣x−4∣=4−x|x-4|=4-x, which is continuous and →4−3=1\to4-3=1 as x→3x\to3. …

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