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Exercise 11.5 · Q13

Q.exlog⁡aexe^{x\log a}e^{x}

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Recognising exlog⁡ae^{x\log a} as axa^x lets both exponential factors combine into a single base.

Step 1. Simplify the first factor. exlog⁡a=elog⁡(ax)=axe^{x\log a}=e^{\log(a^x)}=a^x.

Step 2. Combine with the second factor. ax⋅ex=(ae)xa^x\cdot e^x=(ae)^x. …

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