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Exercise 11.5 · Q17

Q.x+1(x+2)(x+3)\dfrac{x+1}{(x+2)(x+3)}

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A proper fraction with two distinct linear factors in the denominator splits directly into two log-type integrals.

Step 1. Set up partial fractions. x+1(x+2)(x+3)=Ax+2+Bx+3\dfrac{x+1}{(x+2)(x+3)}=\dfrac{A}{x+2}+\dfrac{B}{x+3}, so x+1=A(x+3)+B(x+2)x+1=A(x+3)+B(x+2).

Step 2. Solve for AA. At x=−2x=-2: −1=A(1)⇒A=−1-1=A(1)\Rightarrow A=-1.

Step 3. Solve for BB. At x=−3x=-3: −2=B(−1)⇒B=2-2=B(-1)\Rightarrow B=2. …

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