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Mathematics · Ch 12 — Introduction to Probability Theory

Independent Events

12.6.1

Independent Events

Definition 12.15 -- independent events. Events are said to be independent if the occurrence or non-occurrence of one of them does not affect the probability of the occurrence or non-occurrence of the other. Formally, two events AA and BB are independent if and only if

P(A∩B)=P(A)⋅P(B).P(A\cap B)=P(A)\cdot P(B).

Note 12.6. (1) This is exactly equivalent to P(A/B)=P(A)P(A/B)=P(A) (when P(B)>0P(B)>0) and P(B/A)=P(B)P(B/A)=P(B) (when P(A)>0P(A)>0) -- independence means the conditional probability collapses back to the plain, unconditional probability; knowing one event happened genuinely tells you nothing new about the other. (2) The events A1,A2,…,AnA_1,A_2,\ldots,A_n are mutually independent if EVERY sub-collection satisfies the product rule: P(A1∩A2∩⋯∩An)=P(A1)⋅P(A2)⋯P(An)P(A_1\cap A_2\cap\cdots\cap A_n)=P(A_1)\cdot P(A_2)\cdots P(A_n) (and every smaller sub-collection too).

Theorem 12.8. If AA and BB are independent, then: (i) Aˉ\bar A and BB are independent; (ii) AA and Bˉ\bar B are independent; (iii) Aˉ\bar A and Bˉ\bar B are also independent. Proof of (i): since A,BA,B are independent, P(A∩B)=P(A)P(B)P(A\cap B)=P(A)P(B). By De Morgan's law, P(Aˉ∩Bˉ)=P(A∪B‾)=1−P(A∪B)=1−[P(A)+P(B)−P(A∩B)]=1−P(A)−P(B)+P(A)P(B)=[1−P(A)][1−P(B)]=P(Aˉ)⋅P(Bˉ)P(\bar A\cap\bar B)=P(\overline{A\cup B})=1-P(A\cup B)=1-[P(A)+P(B)-P(A\cap B)]=1-P(A)-P(B)+P(A)P(B)=[1-P(A)][1-P(B)]=P(\bar A)\cdot P(\bar B), which proves Aˉ,Bˉ\bar A,\bar B are independent (part iii); parts (i) and (ii) follow by the same style of argument.

Note 12.7. Independence is a property of PROBABILITY, but mutual exclusiveness is a SET-THEORETIC property. Independent events are identified from their probability VALUES (P(A∩B)P(A\cap B) compared with P(A)P(B)P(A)P(B)); mutually exclusive events are identified from the EVENTS themselves (A∩B=∅A\cap B=\varnothing or not).

Theorem 12.9. Suppose A,BA,B are two events with P(A)≠0,P(B)≠0P(A)\ne0, P(B)\ne0. (1) If A,BA,B are mutually exclusive, they CANNOT be independent. (2) If A,BA,B are independent, they CANNOT be mutually exclusive (without proof). The reason for (1): independence would require P(A∩B)=P(A)P(B)>0P(A\cap B)=P(A)P(B)>0 (a strictly positive value, since both factors are positive), but mutual exclusivity requires P(A∩B)=0P(A\cap B)=0 -- these two requirements directly contradict each other, so genuinely non-trivial mutually exclusive events can never also be independent. …