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Exercise 3.3 · Q5

Q.Find all the angles between 0∘0^\circ and 360∘360^\circ which satisfy the equation sin⁡2θ=34\sin^2\theta=\dfrac34.

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Taking the square root splits the problem into sin⁡θ=32\sin\theta=\dfrac{\sqrt3}{2} (sine positive — Quadrants I, II) and sin⁡θ=−32\sin\theta=-\dfrac{\sqrt3}{2} (sine negative — Quadrants III, IV), each solved by the standard reference angle 60∘60^\circ.

Step 1. Take the square root. sin⁡2θ=34⇒sin⁡θ=±32\sin^2\theta=\dfrac34\Rightarrow\sin\theta=\pm\dfrac{\sqrt3}{2}.

Step 2. Case sin⁡θ=32\sin\theta=\dfrac{\sqrt3}{2} (positive — Quadrants I and II). The reference angle is 60∘60^\circ (since sin⁡60∘=32\sin60^\circ=\dfrac{\sqrt3}{2}).

  • Quadrant I: θ=60∘\theta=60^\circ.
  • Quadrant II: θ=180∘−60∘=120∘\theta=180^\circ-60^\circ=120^\circ.

Step 3. Case sin⁡θ=−32\sin\theta=-\dfrac{\sqrt3}{2} (negative — Quadrants III and IV). Same reference angle 60∘60^\circ, now placed in III/IV.

  • Quadrant III: θ=180∘+60∘=240∘\theta=180^\circ+60^\circ=240^\circ. …

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