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I. Multiple Choice Questions · Q10

Q.If the mass and radius of the Earth are both doubled, then the acceleration due to gravity g′g'

(a) remains the same
(b) g2\dfrac{g}{2}
(c) 2g2g
(d) 4g4g
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Step 1. The formula for surface gravity is g=GMR2g=\dfrac{GM}{R^2}.

Step 2. Substituting M→2MM\to2M and R→2RR\to2R: g′=G(2M)(2R)2=2GM4R2=12⋅GMR2=g2g'=\dfrac{G(2M)}{(2R)^2}=\dfrac{2GM}{4R^2}=\dfrac{1}{2}\cdot\dfrac{GM}{R^2}=\dfrac{g}{2}.

Step 3. The mass doubling alone would double gg, but the radius doubling divides gg by 44 (since RR is squared in the denominator); combined, the net effect is a factor of 2/4=1/22/4=1/2. …

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