Skip to content
III. Long Answer Questions · Q5

Q.Prove that at points near the surface of the Earth, the gravitational potential energy of the object is U=mghU=mgh.

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★est
26% · 23/88 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. For a mass mm at height hh above Earth's surface, its distance from Earth's centre is r=Re+hr=R_e+h, so its general potential energy is

U=−GMemRe+h=−GMemRe(1+hRe)−1.U=-\frac{GM_em}{R_e+h}=-\frac{GM_em}{R_e}\left(1+\frac{h}{R_e}\right)^{-1}.

Step 2. Since h≪Reh\ll R_e near the surface, apply the binomial approximation (1+x)−1≈1−x(1+x)^{-1}\approx1-x for small x=h/Rex=h/R_e:

U≈−GMemRe(1−hRe)=−GMemRe+GMemRe2h.U\approx-\frac{GM_em}{R_e}\left(1-\frac{h}{R_e}\right)=-\frac{GM_em}{R_e}+\frac{GM_em}{R_e^2}h.

Step 3. Using GMe/Re2=gGM_e/R_e^2=g (the surface value), the second term becomes mghmgh, so

U≈−mgRe+mgh.U\approx-mgR_e+mgh. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.