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IV. Exercises · Q6

Q.Let the source propagate a sound wave whose intensity at a point (initially) is I. Suppose we consider a case when the amplitude of the sound wave is doubled and the frequency is reduced to one-fourth. Calculate the new intensity of sound at the same point.

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Step 1. The intensity of a wave is proportional to the square of both its amplitude and its (angular) frequency: I∝A2ω2∝A2f2I\propto A^2\omega^2\propto A^2f^2, since the power radiated by an oscillating source scales with the square of its amplitude and the square of its frequency.

Step 2. The amplitude is doubled, Anew=2AoldA_{new}=2A_{old}, contributing a factor of 22=42^2=4 to the intensity.

Step 3. The frequency is reduced to one-fourth, fnew=fold/4f_{new}=f_{old}/4, contributing a factor of (1/4)2=1/16(1/4)^2=1/16 to the intensity. …

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