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Exercises · Q10

Q.For the same shop (mean ₹5,000, standard deviation ₹800), find the probability that daily sales lie between ₹4,200 and ₹5,800. (Area between Z = 0 and Z = 1.00 is 0.3413.)

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Here μ=5000\mu = 5000, σ=800\sigma = 800.

Z1=4200−5000800=−800800=−1.0Z2=5800−5000800=800800=1.0Z_1 = \dfrac{4200-5000}{800} = \dfrac{-800}{800} = -1.0 \qquad\qquad Z_2 = \dfrac{5800-5000}{800} = \dfrac{800}{800} = 1.0 …

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