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Question 34 of 37

Q.If X∼N(5,25)X \sim N(5, 25) then the standard normal variate Z will be :

(a) Z=X−55Z = \frac{X - 5}{5}
(b) Z=X−255Z = \frac{X - 25}{5}
(c) Z=X−2525Z = \frac{X - 25}{25}
(d) Z=X−525Z = \frac{X - 5}{25}
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N(5,25)N(5,25) means μ=5\mu=5 and variance σ2=25\sigma^2=25, so σ=5\sigma=5 and Z=X−55Z=\tfrac{X-5}{5}.

The notation X∼N(μ,σ2)X\sim N(\mu,\sigma^2) gives the mean μ\mu and the variance σ2\sigma^2 (not the standard deviation) as the two parameters. So here

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