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Question 27 of 37

Q.Using the Standard normal table the sum of the probabilities to the right of z=2.18z=2.18 and to the left of z=−1.75z=-1.75 is :

(a) 0.0146
(b) 0.4854
(c) 0.0547
(d) 0.4599
Tamil Nadu DgeTamil Nadu HSC (DGE) Commerce Board 2024MCQ· 1mImportance★★★★★
73% · 27/37 Questions
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P(Z>2.18)+P(Z<−1.75)=0.0146+0.0401=0.0547P(Z>2.18)+P(Z<-1.75)=0.0146+0.0401=0.0547.

The standard normal table gives the area between 00 and zz:

P(Z>2.18)=0.5−P(0<Z<2.18)=0.5−0.4854=0.0146,P(Z>2.18)=0.5-P(0<Z<2.18)=0.5-0.4854=0.0146,

P(Z<−1.75)=0.5−P(0<Z<1.75)=0.5−0.4599=0.0401.P(Z<-1.75)=0.5-P(0<Z<1.75)=0.5-0.4599=0.0401. …

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