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Choose the Best Answer · Q9

Q.The ionic radii of A+A^+ and B−B^- are 0.98×10−100.98 \times 10^{-10} m and 1.81×10−101.81 \times 10^{-10} m. The coordination number of each ion in AB is

(a) 8
(b) 2
(c) 6
(d) 4
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Step 1. Radius ratio rA+rB−=0.98×10−101.81×10−10=0.541\dfrac{r_{A^+}}{r_{B^-}} = \dfrac{0.98\times10^{-10}}{1.81\times10^{-10}} = 0.541.

Step 2. From the radius-ratio table, a ratio between 0.414 and 0.732 corresponds to an octahedral arrangement with coordination number 6 (the NaCl-type range) …

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