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Question 80 of 122

Q.If (m−5)+i(n+4)(m-5)+i(n+4) is the complex conjugate of (2m+3)+i(3n−2)(2m+3)+i(3n-2) then (n,m)(n, m) are :

(a) (−12,−8)\left(\dfrac{-1}{2}, -8\right)
(b) (−12,8)\left(\dfrac{-1}{2}, 8\right)
(c) (12,−8)\left(\dfrac{1}{2}, -8\right)
(d) (12,8)\left(\dfrac{1}{2}, 8\right)
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017MCQ· 1mImportance★★★★★
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Comparing real and imaginary parts after conjugating gives m=−8m=-8 and n=−12n=-\dfrac12, i.e. (n,m)=(−12,−8)(n,m)=\left(-\dfrac12,-8\right).

  1. The complex conjugate of (2m+3)+i(3n−2)(2m+3)+i(3n-2) is (2m+3)−i(3n−2)(2m+3)-i(3n-2).
  2. Given: (m−5)+i(n+4)=(2m+3)−i(3n−2)(m-5)+i(n+4) = (2m+3)-i(3n-2).
  3. Equate real parts: m−5=2m+3⇒−m=8⇒m=−8m-5 = 2m+3 \Rightarrow -m = 8 \Rightarrow m=-8. …

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