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Question 119 of 122

Q.If zz is a complex number such that z∈C∖Rz\in C\setminus R and z+1z∈Rz+\dfrac1z\in R, then ∣z∣|z| is :

(a) 22
(b) 00
(c) 33
(d) 11
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2026MCQ· 1mImportance★★★★★
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Writing zz in polar form, the imaginary part of z+1/zz+1/z must vanish; since zz is non-real this forces r=1/rr=1/r, i.e. ∣z∣=1|z|=1.

  1. Let z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta) with r=∣z∣>0r=|z|>0. Since z∈C∖Rz\in C\setminus R, sin⁡θ≠0\sin\theta\ne0.
  2. 1z=1r(cos⁡θ−isin⁡θ)\dfrac1z=\dfrac1r(\cos\theta-i\sin\theta) (since 1cos⁡θ+isin⁡θ=cos⁡θ−isin⁡θ\dfrac1{\cos\theta+i\sin\theta}=\cos\theta-i\sin\theta).
  3. z+1z=(r+1r)cos⁡θ+i(r−1r)sin⁡θz+\dfrac1z=\left(r+\dfrac1r\right)\cos\theta+i\left(r-\dfrac1r\right)\sin\theta. …

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