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Question 110 of 122

Q.If ∣z1∣=1|z_1|=1, ∣z2∣=2|z_2|=2, ∣z3∣=3|z_3|=3 and ∣9z1z2+4z1z3+z2z3∣=12|9z_1z_2+4z_1z_3+z_2z_3|=12 then the value of ∣z1+z2+z3∣|z_1+z_2+z_3| is :

(a) 33
(b) 11
(c) 44
(d) 22
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2024MCQ· 1mImportance★★★★★
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Rewrites each conjugate as zˉk=∣zk∣2/zk\bar z_k=|z_k|^2/z_k to recognise the given expression as z1z2z3(zˉ1+zˉ2+zˉ3)z_1z_2z_3(\bar z_1+\bar z_2+\bar z_3), then uses ∣wˉ∣=∣w∣|\bar w|=|w|.

  1. Since ∣z1∣=1|z_1|=1: zˉ1=1z1\bar z_1=\dfrac{1}{z_1}. Since ∣z2∣=2|z_2|=2: zˉ2=4z2\bar z_2=\dfrac{4}{z_2}. Since ∣z3∣=3|z_3|=3: zˉ3=9z3\bar z_3=\dfrac{9}{z_3}.
  2. Consider z1z2z3(zˉ1+zˉ2+zˉ3)=z1z2z3(1z1+4z2+9z3)=z2z3+4z1z3+9z1z2z_1z_2z_3(\bar z_1+\bar z_2+\bar z_3)=z_1z_2z_3\left(\dfrac1{z_1}+\dfrac4{z_2}+\dfrac9{z_3}\right)=z_2z_3+4z_1z_3+9z_1z_2, which is exactly the given expression 9z1z2+4z1z3+z2z39z_1z_2+4z_1z_3+z_2z_3.
  3. So 9z1z2+4z1z3+z2z3=z1z2z3(zˉ1+zˉ2+zˉ3)9z_1z_2+4z_1z_3+z_2z_3=z_1z_2z_3(\bar z_1+\bar z_2+\bar z_3), hence ∣9z1z2+4z1z3+z2z3∣=∣z1z2z3∣⋅∣zˉ1+zˉ2+zˉ3∣|9z_1z_2+4z_1z_3+z_2z_3|=|z_1z_2z_3|\cdot|\bar z_1+\bar z_2+\bar z_3|. …

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