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Question 84 of 122

Q.If α\alpha and β\beta are complex conjugates to each other and α=−2+i\alpha = -\sqrt2 + i then find α2+β2−αβ\alpha^2 + \beta^2 - \alpha\beta.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017Subjective· 6mImportance★★★★★
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Use α+β\alpha+\beta and αβ=∣α∣2\alpha\beta=|\alpha|^2 to compute α2+β2−αβ\alpha^2+\beta^2-\alpha\beta without expanding powers of ii directly.

  1. Given α=−2+i\alpha = -\sqrt2+i and, since β\beta is the complex conjugate of α\alpha, β=αˉ=−2−i\beta=\bar\alpha=-\sqrt2-i.
  2. α+β=(−2+i)+(−2−i)=−22\alpha+\beta = (-\sqrt2+i)+(-\sqrt2-i) = -2\sqrt2.
  3. αβ=ααˉ=∣α∣2=(−2)2+12=2+1=3\alpha\beta = \alpha\bar\alpha = |\alpha|^2 = (-\sqrt2)^2+1^2 = 2+1=3. …

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