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Exercise 8.2 · Q11

Q.A coat of paint of thickness 0.20.2 cm is applied to the faces of a cube whose edge is 1010 cm. Use the differentials to find approximately how many cubic centimeters of paint is used to paint this cube. Also calculate the exact amount of paint used to paint this cube.

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Painting a 0.20.2 cm coat onto every face of the cube extends each pair of opposite faces outward by 0.20.2 cm each, so every edge effectively grows by 2(0.2)=0.42(0.2)=0.4 cm; use the differential of V=x3V=x^3 for the approximate paint volume, then compute the exact difference for comparison.

Step 1. Set up the cube's volume. V(x)=x3V(x)=x^3, base edge x0=10x_0=10 cm.

Step 2. Determine the effective edge increment. A coat of thickness 0.20.2 cm on the OUTSIDE of each face means, along any one dimension, BOTH bounding faces gain 0.20.2 cm, so the edge length increases by a total Δx=2(0.2)=0.4\Delta x=2(0.2)=0.4 cm (new edge =10.4=10.4 cm).

Step 3. Approximate paint volume via the differential. V′(x)=3x2V'(x)=3x^2, so

dV=V′(x0) Δx=3(10)2(0.4)=3(100)(0.4)=120 cm3.dV = V'(x_0)\,\Delta x = 3(10)^2(0.4) = 3(100)(0.4) = 120 \text{ cm}^3.

Step 4. Exact paint volume. Exact volume of paint == volume of the painted (larger) cube −- volume of the original cube: …

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