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Exercise 8.2 · Q4

Q.Assuming log⁡10e=0.4343\log_{10}e=0.4343, find an approximate value of log⁡101003\log_{10}1003.

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Take f(x)=log⁡10xf(x)=\log_{10}x with base point x0=1000x_0=1000 (a clean power of 1010) and dx=3dx=3; use f′(x)=log⁡10exf'(x)=\dfrac{\log_{10}e}{x} (change-of-base of the natural-log derivative).

Step 1. Choose ff and the base point. f(x)=log⁡10xf(x)=\log_{10}x, x0=1000x_0=1000, dx=1003−1000=3dx=1003-1000=3.

Step 2. Compute f(x0)f(x_0). f(1000)=log⁡101000=3f(1000)=\log_{10}1000=3 (exact, since 103=100010^3=1000). …

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