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Question 84 of 99

Q.Find dfdf for f(x)=x2+3xf(x)=x^2+3x and evaluate it for x=2x=2 and dx=0.1dx=0.1.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2022Subjective· 2mImportance★★★★★
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Differentiates f to get the differential formula, then substitutes the given x and dx to get a numerical value.

  1. Given f(x)=x2+3xf(x)=x^2+3x, differentiate: f′(x)=2x+3f'(x)=2x+3.
  2. The differential is df=f′(x) dx=(2x+3) dxdf=f'(x)\,dx=(2x+3)\,dx. …

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