Skip to content
Question 95 of 99

Q.If u(x,y)=x2y+3xy4u(x, y)=x^2y+3xy^4, x=etx=e^t and y=sin⁡ty=\sin t, find dudt\dfrac{du}{dt}

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2025Subjective· 3mImportance★★★★★
96% · 95/99 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Applies the chain rule for a function of two variables, each depending on the single parameter tt: dudt=∂u∂xdxdt+∂u∂ydydt\dfrac{du}{dt}=\dfrac{\partial u}{\partial x}\dfrac{dx}{dt}+\dfrac{\partial u}{\partial y}\dfrac{dy}{dt}.

  1. Given u(x,y)=x2y+3xy4u(x,y)=x^2y+3xy^4, x=etx=e^t, y=sin⁡ty=\sin t.
  2. Compute the partial derivatives of uu: ∂u∂x=2xy+3y4\dfrac{\partial u}{\partial x}=2xy+3y^4 (treat yy as constant), ∂u∂y=x2+12xy3\dfrac{\partial u}{\partial y}=x^2+12xy^3 (treat xx as constant).
  3. Compute the ordinary derivatives of xx and yy with respect to tt: dxdt=et\dfrac{dx}{dt}=e^t, dydt=cos⁡t\dfrac{dy}{dt}=\cos t.
  4. Apply the chain rule for a composite function of one parameter through two intermediate variables: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.