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III. Long Answer Questions · Q9

Q.Derive an expression for the electrostatic potential energy of a dipole in a uniform electric field.

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Step 1. Reference angle. Take θ0=90∘\theta_0=90^\circ (dipole perpendicular to the field) as the zero of potential energy.

Step 2. Work to rotate. Rotating the dipole from 90∘90^\circ to a general angle θ\theta against the torque τ=pEsin⁡θ\tau=pE\sin\theta requires work W=∫90∘θpEsin⁡θ′ dθ′=pE[−cos⁡θ−(−cos⁡90∘)]=−pEcos⁡θW=\displaystyle\int_{90^\circ}^{\theta}pE\sin\theta'\,d\theta'=pE\left[-\cos\theta-(-\cos90^\circ)\right]=-pE\cos\theta.

Step 3. Result. This work equals the potential energy at angle θ\theta: U(θ)=−pEcos⁡θ=−p⃗⋅E⃗U(\theta)=-pE\cos\theta=-\vec{p}\cdot\vec{E}. …

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