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Exercises · 10.14

Q.Why is Li2CO3 decomposed at a lower temperature whereas Na2CO3 at higher temperature?

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Step 1: Recall the trend behind carbonate stability

Alkali metal carbonates are thermally destabilised by a cation with a high charge density (high polarising power), because such a cation pulls electron density from the carbonate ion, weakening its C–O bonding and favouring decomposition to the metal oxide and CO2_2.

Step 2: Compare Li+^+ and Na+^+

Li+^+ is the smallest alkali metal cation, giving it the highest charge density and polarising power in the group. Na+^+ is considerably larger, so it polarises the carbonate ion much less strongly.

Step 3: Apply this to their carbonates

Li2_2CO3_3 therefore decomposes at a comparatively low temperature:

Li2CO3→ΔLi2O+CO2Li_2CO_3 \xrightarrow{\Delta} Li_2O + CO_2

while Na2_2CO3_3 is far more thermally stable and requires much higher temperatures to decompose (it does not decompose readily even on strong heating).

Step 4: Note the diagonal relationship …

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