Q.How would you explain the following observations?
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Start your 14-day free trial to unlock the full solution →(i) BeO almost insoluble but BeSO soluble
BeO consists of two small, similarly-sized ions (Be and O), which gives it an exceptionally high lattice enthalpy that hydration enthalpy cannot overcome, so BeO is essentially insoluble (this also mirrors why alkaline earth oxide/hydroxide solubility rises down the group — Be being the smallest cation gives the least soluble oxide/hydroxide). BeSO, however, pairs the very small Be with the much larger sulphate ion; when a small cation is paired with a large anion, the lattice enthalpy is comparatively lower (dominated by the large anion, similar to a large-cation/small-anion mismatch) and the very high hydration enthalpy of the small Be ion is enough to overcome it, making BeSO soluble.
(ii) BaO soluble but BaSO insoluble
With the small oxide ion, lattice enthalpy is controlled mainly by the (comparatively small) anion, and as we saw for the hydroxides (Example 4), solubility of the Group 2 oxide/hydroxide series increases down the group, so the large Ba pairs favourably enough with the small O for BaO to be soluble. In BaSO, however, the anion itself is large, so lattice enthalpy stays high regardless of cation size, while Ba's hydration enthalpy (already low, being the largest Group 2 cation) is too small to compensate — so BaSO is insoluble (this is exactly the carbonate/sulphate trend of Example 5, where solubility falls down the group).
(iii) LiI more soluble than KI in ethanol …
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