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Physics · Ch 7 — System of Particles and Rotational Motion

Summary

Summary

  • Centre of mass of a system is the weighted average position: R⃗CM=∑mir⃗i∑mi\vec{R}_{\text{CM}} = \frac{\sum m_i \vec{r}_i}{\sum m_i}. For a rigid body, it behaves as if the entire mass is concentrated there for translational motion.
  • Newton’s second law for a system: F⃗ext=Ma⃗CM\vec{F}_{\text{ext}} = M \vec{a}_{\text{CM}}, where F⃗ext\vec{F}_{\text{ext}} is the net external force. Internal forces cancel in pairs and do not affect the CM motion.
  • Angular velocity ω⃗\vec{\omega} and angular acceleration α⃗\vec{\alpha}: α⃗=dω⃗dt\vec{\alpha} = \frac{d\vec{\omega}}{dt}. For pure rotation about a fixed axis, every particle has the same ω\omega.
  • Torque about a point: τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}. Magnitude τ=rFsin⁡θ\tau = rF\sin\theta. Net external torque causes angular acceleration.
  • Angular momentum of a particle: L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p}. For a rigid body rotating about a fixed axis: L=IωL = I\omega, where II is the moment of inertia.
  • Relation between torque and angular momentum: τ⃗ext=dL⃗dt\vec{\tau}_{\text{ext}} = \frac{d\vec{L}}{dt}. If τ⃗ext=0\vec{\tau}_{\text{ext}} = 0, angular momentum is conserved.
  • Moment of inertia I=∑miri2I = \sum m_i r_i^2 for discrete masses; I=∫r2dmI = \int r^2 dm for continuous bodies. It depends on the axis of rotation. …