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Mathematics · Ch 1 — Integrals

Evaluation of Definite Integrals by Substitution

1.9

Evaluation of Definite Integrals by Substitution

Evaluation of Definite Integrals by Substitution

The method of substitution, used extensively for indefinite integrals, adapts to evaluate definite integrals directly. The key insight: when you change the variable of integration, you must also change the limits of integration to match the new variable. This eliminates the need to substitute back to the original variable before applying the limits.

Two Approaches

Approach 1 (resubstitute):

  1. Consider the indefinite integral ∫f(x) dx\int f(x)\,dx and make a substitution to reduce it to a known form.
  2. Integrate with respect to the new variable, omitting the constant of integration.
  3. Resubstitute to express the result in terms of the original variable.
  4. Evaluate at x=ax = a and x=bx = b and take the difference.

Approach 2 (change the limits — direct method):

  1. Choose the substitution t=g(x)t = g(x) that simplifies the integrand, and express dxdx in terms of dtdt by differentiating it.
  2. Change the limits: if x=ax = a then t=g(a)t = g(a); if x=bx = b then t=g(b)t = g(b).
  3. Rewrite the entire integral in terms of tt with the new limits, and evaluate ∫g(a)g(b)g(t) dt\int_{g(a)}^{g(b)} g(t)\,dt directly.
Tip

The second approach is generally faster because it avoids resubstituting. Once you change the limits, you work entirely in the new variable.

Important

The substitution must be one-to-one on [a,b][a, b] for the limit change to be valid. For the functions encountered in this course, this condition is typically satisfied.

The substitution method for definite integrals:

∫abf(g(x))⋅g′(x) dx=∫g(a)g(b)f(t) dt\int_a^b f(g(x))\cdot g'(x)\,dx = \int_{g(a)}^{g(b)} f(t)\,dt

where t=g(x)t = g(x) and dt=g′(x) dxdt = g'(x)\,dx.

Exercise 7.9 — Key Substitutions

  1. ∫01x1+x2 dx\int_0^1 \frac{x}{1+x^2}\,dx — Put t=1+x2t = 1+x^2
  2. ∫0π/2sin⁡5ϕcos⁡ϕ dϕ\int_0^{\pi/2} \sin^5\phi\cos\phi\,d\phi — Put t=sin⁡ϕt = \sin\phi
  3. ∫012sin⁡−1x1+x2 dx\int_0^1 \frac{2\sin^{-1}x}{1+x^2}\,dx — Put t=sin⁡−1xt = \sin^{-1}x
  4. ∫02xx+2 dx\int_0^2 x\sqrt{x+2}\,dx — Put x+2=t2x+2 = t^2
  5. ∫0π/2sin⁡x1+cos⁡2x dx\int_0^{\pi/2} \frac{\sin x}{1+\cos^2 x}\,dx — Put t=cos⁡xt = \cos x
  6. ∫02dxx+4−x2\int_0^2 \frac{dx}{x+4-x^2} — Complete the square
  7. ∫−11dxx2+2x+5\int_{-1}^1 \frac{dx}{x^2+2x+5} — Complete the square
  8. ∫12(1x−12x2)e2x dx\int_1^2 \left(\frac{1}{x} - \frac{1}{2x^2}\right)e^{2x}\,dx — Put t=2xt = 2x

Common Pitfalls to Avoid

  • Forgetting to change limits: in the direct method, always compute the new limits before integrating. …