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Question 21 of 37

Q.Find the equation of the common chord of the circles : x2+y2−4x−4y+3=0x^2 + y^2 - 4x - 4y + 3 = 0 and x2+y2−5x−6y+4=0x^2 + y^2 - 5x - 6y + 4 = 0.

Telangana TsbieTelangana Board of Intermediate Education 2020Subjective· 2mImportance★★★★★
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For two intersecting circles S1=0S_1=0 and S2=0S_2=0, the common chord is the line S1−S2=0S_1-S_2=0 (the x2,y2x^2,y^2 terms cancel, leaving a linear equation).

S1≡x2+y2−4x−4y+3=0S_1 \equiv x^2+y^2-4x-4y+3=0

S2≡x2+y2−5x−6y+4=0S_2 \equiv x^2+y^2-5x-6y+4=0

S1−S2S_1-S_2:

(−4x−4y+3)−(−5x−6y+4)(-4x-4y+3)-(-5x-6y+4) …

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