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Question 33 of 37

Q.Find the equation of the radical axis of the following circles : x2+y2−3x−4y+5=0x^2 + y^2 - 3x - 4y + 5 = 0, 3(x2+y2)−7x+8y−11=03(x^2 + y^2) - 7x + 8y - 11 = 0.

Telangana TsbieTelangana Board of Intermediate Education 2023Subjective· 2mImportance★★★★★
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Normalising the second circle and subtracting gives the radical axis x+10y−13=0x + 10y - 13 = 0.

The radical axis is obtained by subtracting the two circle equations, each written with coefficient 11 for x2x^2 and y2y^2.

S1:x2+y2−3x−4y+5=0S_1: x^2 + y^2 - 3x - 4y + 5 = 0.

S2:3(x2+y2)−7x+8y−11=0⇒x2+y2−73x+83y−113=0S_2: 3(x^2+y^2) - 7x + 8y - 11 = 0 \Rightarrow x^2 + y^2 - \tfrac73 x + \tfrac83 y - \tfrac{11}{3} = 0.

Radical axis S1−S2=0S_1 - S_2 = 0:

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