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Question 35 of 37

Q.Find the equation of the common chord of the circles x2+y2+2x+3y+1=0x^2 + y^2 + 2x + 3y + 1 = 0, x2+y2+4x+3y+2=0x^2 + y^2 + 4x + 3y + 2 = 0.

Telangana TsbieTelangana Board of Intermediate Education 2025Subjective· 2mImportance★★★★★
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Subtracting the two circle equations gives the common chord S1−S2=0S_1-S_2=0, i.e. 2x+1=02x+1=0.

For two circles S1=0S_1=0 and S2=0S_2=0 (each with unit coefficients of x2,y2x^2,y^2), the common chord is S1−S2=0S_1-S_2=0.

S1=x2+y2+2x+3y+1,S2=x2+y2+4x+3y+2.S_1=x^2+y^2+2x+3y+1,\qquad S_2=x^2+y^2+4x+3y+2.

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