Q.Find and write the output of the following python code: Msg1="WeLcOME" Msg2="GUeSTs" Msg3="" for I in range(0,len(Msg2)+1): if Msg1[I]>="A" and Msg1[I]<="M": Msg3=Msg3+Msg1[I] elif Msg1[I]>="N" and Msg1[I]<="Z": Msg3=Msg3+Msg2[I] else: Msg3=Msg3+"*" print Msg3

Rules: loop runs I = 0…6 (range(0, len("GUeSTs")+1) = range(0,7)), covering all 7 chars of Msg1 = "WeLcOME". A–M chars are copied from Msg1; N–Z chars are replaced by Msg2[I]; anything else (all lowercase letters — their codes exceed 'Z') becomes *.

Concept — why lowercase letters always become *

This is Python-2 era code (print Msg3 is the Python 2 print statement). String comparisons use character codes: uppercase letters occupy 65–90 ('A'–'Z') and lowercase letters occupy 97–122 ('a'–'z'). A lowercase letter like 'e' (code 101) satisfies 'e' >= "N" but fails 'e' <= "Z" because 101 > 90 — so no lowercase letter can pass either uppercase band test, and every lowercase character lands in the else branch and appends *.

The loop bound is range(0, len(Msg2)+1). len("GUeSTs") is 6, so the loop runs for I = 0, 1, 2, 3, 4, 5, 6 — exactly the 7 indices of Msg1 = "WeLcOME".

The three branches:

• "A" <= Msg1[I] <= "M" → append Msg1[I] itself,
• "N" <= Msg1[I] <= "Z" → append Msg2[I] (same index, other string),
• otherwise → append "*".

Step-by-step trace