Q.Given the following dictionary Day={1:"Monday", 2: "Tuesday", 3: "Wednesday"} Which statement will return "Tuesday".

The pop() method for Python dictionaries removes the item associated with a specified key and returns its corresponding value.

1. The Day dictionary is {1: "Monday", 2: "Tuesday", 3: "Wednesday"}.
2. Day.pop() (option a) is invalid for dictionaries and would raise a TypeError as it requires a key argument.
3. Day.pop(2) (option b) targets the key 2. The value associated with key 2 is "Tuesday". This method call will remove the (2, "Tuesday") pair and return "Tuesday". …

Concept and Intuition

In Python, dictionaries store data as key-value pairs. The pop() method is used to remove a specific key-value pair from a dictionary. Crucially, it returns the value associated with the key that was removed. This is different from methods like del dict[key], which removes the item but doesn't return anything.

The pop() method requires at least one argument: the key of the item you want to remove.

• If the key exists in the dictionary, pop(key) removes the key-value pair and returns the value.
• If the key does not exist, pop(key) raises a KeyError.
• You can also provide a second optional argument, default_value, like pop(key, default_value). If the key is not found, it returns default_value instead of raising a KeyError.

We are looking for the statement that will return the string "Tuesday". This means we need to identify which option correctly uses pop() to target the key associated with "Tuesday".

Step-by-step Solution

Let's analyze each option given the dictionary Day = {1: "Monday", 2: "Tuesday", 3: "Wednesday"}.

1. Analyze option (a) Day.pop()

   • This statement attempts to call pop() without any arguments.
   • As explained in the concept, the dictionary pop() method requires a key.
   • Executing Day.pop() will raise a TypeError.
   • Therefore, this statement will not return "Tuesday".

2. Analyze option (b) Day.pop(2)

   • This statement calls pop() with the argument 2.
   • In our dictionary Day, the key 2 exists, and its corresponding value is "Tuesday".
   • Day.pop(2) will remove the key-value pair (2: "Tuesday") from the dictionary and return the value "Tuesday". …