Q.Consider the given expression : 7<4 or 6>3 and not 10==10 or 17>4 Which of the following will be the correct output if the given expression is evaluated ?

Concept: Boolean operator precedence and short-circuit evaluation in logical expressions.

Python evaluates boolean operators in the order: not (highest), and, then or (lowest). We work through the expression left-to-right respecting precedence.

Given: 7<4 or 6>3 and not 10==10 or 17>4

Step 1: Evaluate comparisons:

• 7<4 → False
• 6>3 → True
• 10==10 → True
• 17>4 → True

Expression becomes: False or True and not True or True

Step 2: Apply not first:

False or True and False or True …

This is a question about operator precedence in boolean logic, exactly as implemented in most programming languages (Python, C, Java). You need to know which operators "grab" their operands first.

The precedence hierarchy for logical operators is:

1. not (highest - unary, binds to the immediate right)
2. and (middle - binary)
3. or (lowest - binary)

Think of it like arithmetic: not behaves like exponentiation, and like multiplication, and or like addition. Just as 2 + 3 * 4 means 2 + (3 * 4), the expression A or B and C means A or (B and C).

Let me parse the given expression step by step.

Given: 7<4 or 6>3 and not 10==10 or 17>4

1. Evaluate all comparison operators first (they have higher precedence than logical operators):

   • 7 < 4 -> False
   • 6 > 3 -> True
   • 10 == 10 -> True
   • 17 > 4 -> True

   So the expression becomes:

   False or True and not True or True

2. Apply not (highest precedence among logical operators):

   • not True -> False

   Now we have:

   False or True and False or True

3. Apply and (next precedence):

   The and operator sits between True and False:

   • True and False -> False …