Skip to content
NCERT Exemplar · Q10

Q.Correct IUPAC name for H3C—CH(C2H5)—CH(C2H5)—CH3 is ______.

(i) 2-ethyl-3-methylpentane
(ii) 3,4-dimethylhexane
(iii) 2-sec-butylbutane
(iv) 2,3-dimethylbutane
Uttar Pradesh UpmspMCQ· 1mImportance★★★★★est
57% · 74/130 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Trace the longest continuous carbon chain through the ethyl branches: it is six carbons (hexane) bearing a methyl group at C-3 and C-4. The name is 3,4-dimethylhexane — option (ii).

The condensed structure is H3C-CH(C2H5)-CH(C2H5)-CH3\text{H}_3\text{C-CH(C}_2\text{H}_5\text{)-CH(C}_2\text{H}_5\text{)-CH}_3: a four-carbon written backbone with an ethyl group (-C2H5\text{-C}_2\text{H}_5) on each of the two inner carbons. The molecule has 4+2+2=84 + 2 + 2 = 8 carbons in all, so the parent chain must be found by inspection, not read off the written formula.

Find the longest chain. Do not stop at the four-carbon written backbone. Start at the terminal CH3\text{CH}_3 of one ethyl group, pass through the two central carbons, and finish at the CH3\text{CH}_3 of the other ethyl group. This traces a continuous chain of six carbons:

CH3-CH2-CH(CH3)-CH(CH3)-CH2-CH3\text{CH}_3\text{-CH}_2\text{-CH(CH}_3\text{)-CH(CH}_3\text{)-CH}_2\text{-CH}_3

The two carbons that were the original written termini are now methyl substituents on this hexane chain.

Number and name. The two methyl branches sit on the third and fourth carbons; numbering from either end gives the same locant set {3,4}\{3, 4\} by symmetry. Hence the name is 3,4-dimethylhexane.

Checking the other options: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.