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NCERT Exemplar · Q66

Q.A liquid with high boiling point decomposes on simple distillation but it can be steam distilled for its purification. Explain how is it possible?

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Steam distillation works by lowering the boiling point of a mixture below the decomposition temperature of the high-boiling liquid, because the total vapour pressure equals the sum of individual partial pressures, allowing distillation at temperatures far below the liquid's normal boiling point.

Why Steam Distillation Succeeds Where Simple Distillation Fails

When a liquid has a very high boiling point, heating it to that temperature during simple distillation often causes thermal decomposition—the molecules break apart before they can vaporise intact. Steam distillation elegantly sidesteps this problem by exploiting a fundamental principle: immiscible liquids in contact exert their vapour pressures independently.

The key insight is that the mixture doesn't need to reach the boiling point of either pure component. Instead, it boils when the combined vapour pressure reaches atmospheric pressure, and this happens at a temperature lower than the boiling point of either liquid alone.

The Mechanism, Step by Step

  1. Two immiscible liquids, two independent vapour pressures When water (steam) and the organic liquid are together but immiscible, each behaves as if the other weren't there. The water molecules exert their own vapour pressure pwaterp_{\text{water}}, and the organic molecules exert theirs, porganicp_{\text{organic}}. The total pressure above the mixture is simply:

Ptotal=pwater+porganicP_{\text{total}} = p_{\text{water}} + p_{\text{organic}}

  1. Boiling occurs when the sum reaches atmospheric pressure

    The mixture boils when Ptotal=PatmP_{\text{total}} = P_{\text{atm}} (typically 760 mm Hg). Crucially, this condition is met at a temperature below 100 °C—in fact, below the boiling point of water—because both liquids contribute to the total pressure. You don't need to heat the organic liquid anywhere near its own (dangerously high) boiling point.

  2. The organic liquid vaporises at a safe temperature

    Even though the organic compound might normally boil at, say, 250 °C (where it decomposes), in the presence of steam it vaporises at perhaps 95–99 °C. At this lower temperature the molecules remain intact. The steam "carries" the organic vapour over into the condenser.

  3. Separation after condensation

    The vapours condense together, but because the liquids are immiscible they separate into two layers in the receiving flask. You can then simply decant or use a separating funnel to isolate the purified organic liquid.

Ptotal=pwater+porganic=Patmat T<Tb.p. of either pure liquidP_{\text{total}} = p_{\text{water}} + p_{\text{organic}} = P_{\text{atm}} \quad \text{at } T < T_{\text{b.p. of either pure liquid}}

Tip

The molar ratio of the two liquids in the distillate is given by the ratio of their partial pressures (and inversely by their molar masses):

norganicnwater=porganicpwater\frac{n_{\text{organic}}}{n_{\text{water}}} = \frac{p_{\text{organic}}}{p_{\text{water}}} …

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