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Q.What do you understand by resolving power of a microscope? How will resolving power of microscope be affected when –

(i) Wavelength of light used decreases
(ii) Diameter of objective lens decreases
Uttarakhand UbseUttarakhand Board Intermediate (Class 12) 2019Subjective· 3mImportance★★★★★
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R.P. of a microscope =2μsin⁡θλ=\dfrac{2\mu\sin\theta}{\lambda}: smaller λ\lambda raises it; smaller objective diameter lowers it.

Resolving power of a microscope. It is the ability of the microscope to form separate (distinguishable) images of two point objects lying very close together. It is measured by the reciprocal of the smallest distance dmind_{min} between two points that can just be seen as separate:

R.P.=1dmin=2μsin⁡θλ\text{R.P.} = \frac{1}{d_{min}} = \frac{2\mu\sin\theta}{\lambda}

where λ\lambda is the wavelength of light used, μ\mu the refractive index of the medium between object and objective, and θ\theta the half-angle of the cone of light entering the objective (μsin⁡θ\mu\sin\theta = numerical aperture).

Effect of the changes. …

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