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Business Mathematics and Basic Statistics · Ch 8 — Permutations and Combinations

Applications — Arrangement and Selection Problems

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Applications — Arrangement and Selection Problems

Telling a permutation problem from a combination problem

Every word problem in this chapter reduces to one question: if the same objects were chosen in a different order, would the outcome actually be different?

  • Yes → use nPr^{n}P_{r}. Examples: arranging books on a shelf, forming a number from digits, appointing a Chairperson and a Secretary (two DIFFERENT roles), deciding 1st/2nd/3rd prize.
  • No → use nCr^{n}C_{r}. Examples: forming a committee, choosing a team, selecting a set of books to buy (without arranging them).
Note

A useful decision test

Swap two of the chosen items and ask: "is this now a different real-world outcome?" If yes, it is a permutation. If the outcome is identical either way, it is a combination.

Worked reasoning for common problem types

  • Arranging all nn distinct objects in a row: n!n! ways (this is simply nPn^{n}P_{n}).
  • Arranging rr out of nn distinct objects: nPr^{n}P_{r} ways.
  • Selecting rr out of nn distinct objects (no arranging): nCr^{n}C_{r} ways.
  • Selecting AND then arranging rr out of nn objects: this is exactly nPr^{n}P_{r} again — never computed separately as nCr×r!^{n}C_{r} \times r! from scratch, because nCr×r!=nPr^{n}C_{r} \times r! = {}^{n}P_{r} always (the very identity used to derive the nCr^{n}C_{r} formula above).
  • Number of diagonals of a polygon with nn vertices: every pair of vertices gives a line segment (nC2^{n}C_{2} of them in all), and exactly nn of those segments are SIDES of the polygon, not diagonals — so the diagonal count is nC2−n^{n}C_{2} - n. …
Definition 1Permutation or Combination? — The Order Test

Ask: does swapping the order of the chosen items create a genuinely different outcome? If yes (President vs Secretary, 1st vs 2nd prize, a number formed from digits) — use nPr^{n}P_{r}. If no (a committee, a team, a …