Business Mathematics and Basic Statistics · Ch 9 — Sets — Operations and Functions
Revisiting the Null Set — A Subset of Every Set
Revisiting the Null Set — A Subset of Every Set
You already know from the previous chapter that a set is a subset of a set (written ) whenever every element of is also an element of . The empty set deserves special attention here, because a genuinely important — and, at first glance, slightly strange-looking — fact follows directly from this definition.
Theorem — The Empty Set is a Subset of Every Set
For any set , .
Why should this be true, even when itself has nothing to do with ? Go back to the definition: means "every element of is also an element of ." But has no elements at all — so there is nothing to check. The statement "every element of is in " is true simply because there is no element of that could ever fail the test. A statement that is true only because its condition is never actually triggered is called vacuously true — this is exactly that situation, and it is why the theorem holds for every set without exception, including when itself is (then , which is also true, since every set is a subset of itself).
This chapter takes the vocabulary built in the previous chapter — sets, subsets, cardinality, Cartesian products — and puts it to work: combining sets with operations (union, intersection, difference, symmetric difference, complement), picturing those operations with Venn diagrams, counting elements across combined sets with the inclusion-exclusion principle, and finally using sets of ordered pairs to picture functions. The fact that for every set resurfaces almost immediately in the very next section, once we start listing every possible subset of a set — a skill this WBCHSE Class 11 Business Mathematics and Basic Statistics chapter builds from the ground up.
A statement of the form "every element of satisfies condition " that is true simply because has no elements to test — there is nothing that could fail the condition.
if every element of is also an element of . The theorem (for any set ) follows directly, since has no elements that could ever fail the containment test.