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Worked Examples · Example 4

Q.If A={1,2}A = \{1, 2\} and B={3,4,5}B = \{3, 4, 5\}, find A×BA \times B and ∣A×B∣|A \times B|.

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Step 1 — Recall the definition. A×B={(a,b):a∈A,b∈B}A \times B = \{(a,b) : a \in A, b \in B\}, pairing every element of AA (first component) with every element of BB (second component).

Step 2 — List systematically, taking each element of AA in turn.

  • With a=1a = 1: (1,3),(1,4),(1,5)(1,3), (1,4), (1,5)
  • With a=2a = 2: (2,3),(2,4),(2,5)(2,3), (2,4), (2,5)

Step 3 — Combine. A×B={(1,3),(1,4),(1,5),(2,3),(2,4),(2,5)}A \times B = \{(1,3), (1,4), (1,5), (2,3), (2,4), (2,5)\} — 6 pairs in total. …

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