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Example · Example 2

Q.Nitrogen and hydrogen combine to form ammonia according to N2(g)+3H2(g)→2NH3(g)\text{N}_2(g) + 3\text{H}_2(g) \rightarrow 2\text{NH}_3(g). If 10 L10\ \text{L} of N2\text{N}_2 gas is allowed to react completely with hydrogen at constant temperature and pressure, what volume of H2\text{H}_2 is consumed and what volume of NH3\text{NH}_3 is produced? Which law of chemical combination does this illustrate?

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The balanced equation is:

N2(g)+3H2(g)→2NH3(g)\text{N}_2(g) + 3\text{H}_2(g) \rightarrow 2\text{NH}_3(g)

By Gay-Lussac's law of gaseous volumes, at the same temperature and pressure the volumes of reacting gases and gaseous products are in the same ratio as their coefficients in the balanced equation, i.e. N2:H2:NH3=1:3:2\text{N}_2 : \text{H}_2 : \text{NH}_3 = 1 : 3 : 2.

Given: volume of N2=10 L\text{N}_2 = 10\ \text{L}.

Volume of H2\text{H}_2 consumed =3×10 L=30 L= 3 \times 10\ \text{L} = 30\ \text{L}

Volume of NH3\text{NH}_3 produced =2×10 L=20 L= 2 \times 10\ \text{L} = 20\ \text{L}

[!ANSWER] 30 L30\ \text{L} of hydrogen is consumed and 20 L20\ \text{L} of ammonia is produced; this directly illustrates Gay-Lussac's law of gaseous volumes.

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