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Example · Example 4

Q.Calculate the molecular mass of glucose, C6H12O6\text{C}_6\text{H}_{12}\text{O}_6, given the atomic masses C=12.01 u\text{C} = 12.01\ \text{u}, H=1.008 u\text{H} = 1.008\ \text{u}, O=16.00 u\text{O} = 16.00\ \text{u}.

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Glucose has the molecular formula C6H12O6\text{C}_6\text{H}_{12}\text{O}_6, so its molecular mass is the sum of the atomic masses of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms.

M(C6H12O6)=6×M(C)+12×M(H)+6×M(O)M(\text{C}_6\text{H}_{12}\text{O}_6) = 6 \times M(\text{C}) + 12 \times M(\text{H}) + 6 \times M(\text{O})

=6(12.01)+12(1.008)+6(16.00)= 6(12.01) + 12(1.008) + 6(16.00)

=72.06+12.10+96.00= 72.06 + 12.10 + 96.00 …

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