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Exercise · Q11

Q.Sample A of water is decomposed and found to contain 1 g1\ \text{g} of hydrogen and 8 g8\ \text{g} of oxygen. Sample B of water, obtained from a completely different source, is decomposed and found to contain 2 g2\ \text{g} of hydrogen and 16 g16\ \text{g} of oxygen. Show that these observations are consistent with the law of definite proportions.

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Sample A: 1 g1\ \text{g} H and 8 g8\ \text{g} O ⇒\Rightarrow ratio H:O=1:8\text{H}:\text{O} = 1:8.

Sample B: 2 g2\ \text{g} H and 16 g16\ \text{g} O ⇒\Rightarrow ratio H:O=2:16=1:8\text{H}:\text{O} = 2:16 = 1:8.

Even though Sample A and Sample B were obtained from completely different sources and contain very different total masses of water, the ratio of hydrogen to oxygen by mass is identical in both, 1:81:8.

[!ANSWER] Both samples of water show the same hydrogen-to-oxygen mass ratio, 1:81:8, exactly as the law of definite proportions requires — a given compound always has the same elements in the same fixed mass ratio, regardless of its source.

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