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Exercise: Algebra of Functions · Q27

Q.If f(x)=x2+2xf(x) = x^2 + 2x and g(x)=x+1g(x) = x + 1, find the domain and rule of (fg)(x)\left(\dfrac{f}{g}\right)(x). Is x=−1x = -1 in its domain?

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Step 1: f(x)=x2+2x=x(x+2)f(x)=x^2+2x=x(x+2) and g(x)=x+1g(x)=x+1, so (fg)(x)=x(x+2)x+1\left(\dfrac{f}{g}\right)(x)=\dfrac{x(x+2)}{x+1}.

Step 2: g(x)=0g(x)=0 at x=−1x=-1, so this value must be excluded from the domain; since both ff and gg individually have domain R\mathbb{R}, this is the only exclusion. …

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