Skip to content
Miscellaneous · Q28

Q.What does the Cartesian product R×R×R\mathbb{R} \times \mathbb{R} \times \mathbb{R} represent geometrically? Verify that the point (2,−1,3)(2, -1, 3) belongs to it, and explain why (0,0)(0, 0) does not.

West Bengal WbchseTextbookSubjectiveImportance★★★★★est
3% · 1/31 Questions
✓ Free question

Step 1: R×R×R={(x,y,z):x,y,z∈R}\mathbb{R}\times\mathbb{R}\times\mathbb{R}=\{(x,y,z):x,y,z\in\mathbb{R}\} is the set of all ordered triples of real numbers, identified with three-dimensional space (three mutually perpendicular axes through a common origin).

Step 2: (2,−1,3)(2,-1,3) has three real entries 2,−1,32,-1,3, so it fits the defining pattern (x,y,z)(x,y,z) with x=2,y=−1,z=3x=2,y=-1,z=3; hence (2,−1,3)∈R×R×R(2,-1,3)\in\mathbb{R}\times\mathbb{R}\times\mathbb{R}.

Step 3: (0,0)(0,0) has only two entries, so it is an element of R×R\mathbb{R}\times\mathbb{R} (a pair), not of R×R×R\mathbb{R}\times\mathbb{R}\times\mathbb{R} (which requires exactly three entries) — the two sets consist of objects of a different 'shape' (pairs versus triples) and are not comparable this way.

✓Final answer

(2,−1,3)∈R×R×R(2,-1,3)\in\mathbb{R}\times\mathbb{R}\times\mathbb{R}, since it is an ordered triple of reals; (0,0)∉R×R×R(0,0)\notin\mathbb{R}\times\mathbb{R}\times\mathbb{R}, since it has only two components, not three

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.